{"id":89,"date":"2018-09-04T13:59:28","date_gmt":"2018-09-04T11:59:28","guid":{"rendered":"http:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/?page_id=89"},"modified":"2018-11-24T20:03:14","modified_gmt":"2018-11-24T19:03:14","slug":"zdroje-elektrickeho-napeti-a-proudu","status":"publish","type":"page","link":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/zakladni-elektrotechnicke-soucastky-a-jejich-znaceni-pismeny\/zdroje-elektrickeho-napeti-a-proudu\/","title":{"rendered":"Zdroje elektrick\u00e9ho nap\u011bt\u00ed a proudu-zdroj jako dal\u0161\u00ed sou\u010d\u00e1stka"},"content":{"rendered":"<p>Zdroje elekt\u0159iny se d\u011bl\u00ed na:<\/p>\n<ul>\n<li>zdroje nap\u011bt\u00ed<\/li>\n<li>zdroje proudu<\/li>\n<\/ul>\n<h3>Zdroje nap\u011bt\u00ed<\/h3>\n<p>V oblasti <a href=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/zaklady-vzniku-stridaveho-proudu\/\">stejnosm\u011brn\u00e9ho nap\u011bt\u00ed<\/a> a proudu jsou to elektrick\u00e9 \u010dl\u00e1nky funguj\u00edc\u00ed na principu chemick\u00fdch reakc\u00ed a tzv. zdroje <a href=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/zaklady-vzniku-stridaveho-proudu\/\">stejnosm\u011brn\u00e9ho nap\u011bt\u00ed<\/a>, kter\u00e9 se p\u0159ipojuj\u00ed do elektrick\u00e9 z\u00e1suvky a na v\u00fdstupu d\u00e1vaj\u00ed zmen\u0161en\u00e9 nap\u011bt\u00ed st\u00e1l\u00e9 polarity a velikosti.<\/p>\n<p>Elektrick\u00e9 \u010dl\u00e1nky a baterie jsou tyto:<\/p>\n<ul>\n<li>\n<ul>\n<li>tu\u017ekov\u00e9 (nab\u00edjec\u00ed 1,2 V a nenab\u00edjec\u00ed 1,5 V)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-34\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/baterie-1-225x300.jpg\" alt=\"\" width=\"225\" height=\"300\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/baterie-1-225x300.jpg 225w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/baterie-1-768x1024.jpg 768w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/baterie-1.jpg 960w\" sizes=\"auto, (max-width: 225px) 100vw, 225px\" \/><br \/>\n(B\u00fdvaj\u00ed r\u016fzn\u00fdch velikost\u00ed. N\u011bkter\u00e9 men\u0161\u00ed velikosti jsou mikrotu\u017ekov\u00e9. Jsou i v\u011bt\u0161\u00ed velikosti ne\u017e tu\u017ekov\u00e9.)<\/li>\n<li>3Voltov\u00e9 (Slo\u017een\u00e9 ze dvou 1,5Voltov\u00fdch \u010dl\u00e1nk\u016f v s\u00e9rii)<\/li>\n<li>ploch\u00e9 (4,5Voltov\u00e9) (Slo\u017een\u00e9 ze t\u0159\u00ed 1,5Voltov\u00fdch \u010dl\u00e1nk\u016f v s\u00e9rii)<\/li>\n<li>6Voltov\u00e9<\/li>\n<li>9Voltov\u00e9 (Hranat\u00e9) (Slo\u017een\u00e9 ze t\u0159\u00ed 3Voltov\u00fdch \u010dl\u00e1nk\u016f v s\u00e9rii)<\/li>\n<li>knofl\u00edkov\u00e9 (mal\u00e9 kovov\u00e9 kulat\u00e9. R\u016fzn\u00e9 velikosti a r\u016fzn\u00e1 nap\u011bt\u00ed. !!!V\u017edy je zde kladn\u00e9 nap\u011bt\u00ed na v\u011bt\u0161\u00ed kovov\u00e9 \u010d\u00e1sti!!!)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<p>Mo\u017en\u00e1 jsou i jin\u00e9 m\u00e9n\u011b obvykl\u00e9 druhy bateri\u00ed.<\/p>\n<p>V\u00edce jak 9Voltov\u00e9 b\u00fdvaj\u00ed speci\u00e1ln\u00ed velk\u00e9 speci\u00e1ln\u00edho tvaru. T\u0159eba do auta nebo do n\u011bjak\u00fdch p\u0159\u00edstroj\u016f.<\/p>\n<p>P\u0159i p\u0159ipojov\u00e1n\u00ed z\u00e1t\u011b\u017ee (nap\u0159. \u017e\u00e1rovky) k baterii je d\u016fle\u017eit\u00e9 nejen nap\u011bt\u00ed, ale i max. proud, kter\u00fd je schopna dodat. Toti\u017e \u00fapln\u011b d\u016fle\u017eit\u00fd je v\u00fdkon, nejen nap\u011bt\u00ed. <strong>P=U\u00d7I<\/strong>. Ka\u017ed\u00fd zdroj m\u00e1 maxim\u00e1ln\u00ed jmenovit\u00fd proud, kter\u00fd je schopen dodat. Pokud byste p\u0159ipojili z\u00e1t\u011b\u017e s tak mal\u00fdm odporem, \u017ee by musel proch\u00e1zet proud v\u011bt\u0161\u00ed ne\u017e maxim\u00e1ln\u00ed jmenovit\u00fd u zdroje, tak toto je vlastn\u011b zkrat.<br \/>\nMaxim\u00e1ln\u00ed proud proch\u00e1zej\u00edc\u00ed zdrojem nap\u011bt\u00ed ovliv\u0148uje tzv. vnit\u0159n\u00ed odpor zdroje. Ten je sice nepatrn\u00fd. P\u0159i jeho m\u011b\u0159en\u00ed ohmmetrem byste nam\u011b\u0159ili nulu. Ale je podstatn\u00fd.<\/p>\n<p>P\u0159edstavte si to takto:<\/p>\n<p>Nap\u0159. toto je re\u00e1ln\u00fd zdroj nap\u011bt\u00ed:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-92\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/elektrick\u00fd-\u010dl\u00e1nek-300x203.jpg\" alt=\"\" width=\"300\" height=\"203\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/elektrick\u00fd-\u010dl\u00e1nek-300x203.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/elektrick\u00fd-\u010dl\u00e1nek.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><br \/>\nA cel\u00e9 rozkreslen\u00e9 dopodrobna, by to byl v s\u00e9rii ide\u00e1ln\u00ed zdroj nap\u011bt\u00ed s absolutn\u011b nulov\u00fdm vnit\u0159n\u00edm odporem, co\u017e je cel\u00e9 to kulat\u00e9 a nepatrn\u00fd odpor(sou\u010d\u00e1stka), co\u017e je cel\u00e9 to hranat\u00e9 (Ri)<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-90\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-300x203.jpg\" alt=\"\" width=\"300\" height=\"203\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-300x203.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>D\u016fle\u017eit\u00e9!!!: Na ide\u00e1ln\u00edm zdroji nap\u011bt\u00ed je konstantn\u00ed nap\u011bt\u00ed nehled\u011b na jeho z\u00e1t\u011b\u017ei (tzn. nehled\u011b na tom, jak velk\u00fd odpor m\u00e1 spot\u0159ebi\u010d, kter\u00fd k n\u011bmu p\u0159ipoj\u00edte), u re\u00e1ln\u00e9ho zdroje nap\u011bt\u00ed to tak nen\u00ed.<\/p>\n<p><strong>U re\u00e1ln\u00e9ho zdroje: <\/strong><strong>\u010c\u00edm men\u0161\u00ed odpor m\u00e1 spot\u0159ebi\u010d, t\u00edm poklesne na zdroji nap\u011bt\u00ed v\u00edce. A\u017e spot\u0159ebi\u010d odpoj\u00edte, nap\u011bt\u00ed op\u011bt stoupne.<\/strong><\/p>\n<p>Tomu, o kolik poklesne nap\u011bt\u00ed p\u0159i p\u0159ipojen\u00ed z\u00e1t\u011b\u017ee, se \u0159\u00edk\u00e1 <strong>tvrdost zdroje<\/strong>. N\u011bkter\u00e9 zdroje jsou <strong>tvrd\u0161\u00ed<\/strong>, tj.\u00a0<strong>nap\u011bt\u00ed na nich p\u0159i p\u0159ipojen\u00ed z\u00e1t\u011b\u017ee p\u0159\u00edli\u0161 nepoklesne. Maj\u00ed velmi mal\u00fd vnit\u0159n\u00ed odpor Ri.<\/strong> A n\u011bkter\u00e9 jsou <strong>m\u011bk\u010d\u00ed. <\/strong>tj. <strong>nap\u011bt\u00ed na nich p\u0159i p\u0159ipojen\u00ed z\u00e1t\u011b\u017ee poklesne v\u00edce. Maj\u00ed v\u011bt\u0161\u00ed Ri.<\/strong><\/p>\n<p>Funguje to takto:<\/p>\n<p>Pokud p\u0159ipoj\u00edte jen a pouze voltmetr ke zdroji nap\u011bt\u00ed, nam\u011b\u0159\u00edte pln\u00e9 nap\u011bt\u00ed zdroje:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-93\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem-300x203.jpg\" alt=\"\" width=\"300\" height=\"203\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem-300x203.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>A kdy\u017e tam paraleln\u011b s voltmetrem p\u0159ipoj\u00edte je\u0161t\u011b n\u011bjakou z\u00e1t\u011b\u017e, nap\u011bt\u00ed se rozd\u011bl\u00ed mezi z\u00e1t\u011b\u017e a Ri. Dokavad je tam pouze voltmetr, tak se nap\u011bt\u00ed t\u00e9m\u011b\u0159 nerozd\u011bl\u00ed, proto\u017ee voltmetr m\u00e1 hodn\u011b velk\u00fd vnit\u0159n\u00ed odpor.<\/p>\n<p>Zde je to u\u017e rozd\u011blen\u00e9. Zde si v\u0161im\u011bte, \u017ee voltmetr u\u017e vlastn\u011b nem\u011b\u0159\u00ed U na cel\u00e9m obvodu, ale pouze na z\u00e1t\u011b\u017ei (na \u017e\u00e1rovce).:<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-94\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem-a-z\u00e1t\u011b\u017e\u00ed-300x296.jpg\" alt=\"\" width=\"300\" height=\"296\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem-a-z\u00e1t\u011b\u017e\u00ed-300x296.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem-a-z\u00e1t\u011b\u017e\u00ed-100x100.jpg 100w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-nap\u011bt\u00ed-s-voltmetrem-a-z\u00e1t\u011b\u017e\u00ed.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Nyn\u00ed je tedy jasn\u00e9, \u017ee \u010d\u00edm bude men\u0161\u00ed Ri, t\u00edm se na n\u011bm usad\u00ed men\u0161\u00ed nap\u011bt\u00ed a t\u00edm v\u011bt\u0161\u00ed nap\u011bt\u00ed bude na z\u00e1t\u011b\u017ei. A pr\u00e1v\u011b zdroji s <strong>men\u0161\u00edm<\/strong> Ri se \u0159\u00edk\u00e1 <strong>tvrd\u0161\u00ed zdroj<\/strong>. A zdroji s <strong>v\u011bt\u0161\u00edm<\/strong> Ri se \u0159\u00edk\u00e1 <strong>m\u011bk\u010d\u00ed zdroj<\/strong>.<\/p>\n<h3>Zdroje proudu<\/h3>\n<p>Jsou konstruov\u00e1ny elektronicky. Maj\u00ed konstantn\u00ed proud. Ide\u00e1ln\u00ed zdroj proudu m\u00e1 teoreticky nekone\u010dn\u011b velk\u00fd Ri a dok\u00e1\u017ee dodat teoreticky nekone\u010dn\u011b velk\u00e9 nap\u011bt\u00ed. Skute\u010dnost je ale jin\u00e1. Ri je pouze hodn\u011b velk\u00fd. A jeliko\u017e je I proch\u00e1zej\u00edc\u00ed zdrojem konstantn\u00ed p\u0159i v\u0161ech z\u00e1t\u011b\u017e\u00edch, tak nap\u011bt\u00ed mezi body A a B z\u00e1vis\u00ed na p\u0159ipojen\u00e9 z\u00e1t\u011b\u017ei. (Viz. obr\u00e1zek dole.)<\/p>\n<h4>Pozn. \u010c\u00e1st pod odporem Ri je ide\u00e1ln\u00ed zdroj nap\u011bt\u00ed.<\/h4>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-95\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-proudu-300x298.jpg\" alt=\"\" width=\"300\" height=\"298\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-proudu-300x298.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-proudu-150x150.jpg 150w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-proudu-100x100.jpg 100w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/zdroj-proudu.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Pozn.: Zdroj proudu m\u016f\u017eete zkonstruovat tak\u00e9 prost\u00fdm p\u0159ipojen\u00edm rezistoru k z\u00e1t\u011b\u017ei, kdy\u017e je nap\u00e1jena zdrojem nap\u011bt\u00ed.<\/p>\n<p><strong>Se spojov\u00e1n\u00edm zdroj\u016f el. nap\u011bt\u00ed je to takov\u00e9to:<\/strong><\/p>\n<p>Pokud spoj\u00edte\u00a0v\u00edce el. \u010dl\u00e1nk\u016f takto, \u017ee budete spojovat pouze plusy s minusama<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-96\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-1-300x203.jpg\" alt=\"\" width=\"300\" height=\"203\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-1-300x203.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-1.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>je to s\u00e9riov\u00e9 spojen\u00ed a jejich nap\u011bt\u00ed a vnit\u0159n\u00ed odpory se s\u010d\u00edtaj\u00ed. Jeliko\u017e se ale s\u010d\u00edtaj\u00ed vnit\u0159n\u00ed odpory, je celkov\u00fd odpor cel\u00e9 sestavy zdroj\u016f v\u011bt\u0161\u00ed ne\u017e odpor jak\u00e9hokoli samotn\u00e9ho el. \u010dl\u00e1nku. Proud se tedy s\u00e9riov\u00fdm spojov\u00e1n\u00edm zmen\u0161uje.<\/p>\n<p>Pokud spoj\u00edte\u00a0v\u00edce el. \u010dl\u00e1nk\u016f paraleln\u011b, \u017ee spoj\u00edte v\u0161echny + a v\u0161echny -,<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-97\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-2-300x249.jpg\" alt=\"\" width=\"300\" height=\"249\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-2-300x249.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-2.jpg 544w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>tak celkov\u00e9 nap\u011bt\u00ed je rovno nap\u011bt\u00ed \u010dl\u00e1nku s nejvy\u0161\u0161\u00edm nap\u011bt\u00edm a celkov\u00fd maxim\u00e1ln\u00ed proud sestavy je roven sou\u010dtu proud\u016f jednotliv\u00fdch \u010dl\u00e1nk\u016f.<\/p>\n<p>Pokud byste v s\u00e9riov\u00e9m spojen\u00ed n\u011bkter\u00fd \u010dl\u00e1nek zapojili obr\u00e1cen\u011b,<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-98\" src=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-3-300x203.jpg\" alt=\"\" width=\"300\" height=\"203\" srcset=\"https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-3-300x203.jpg 300w, https:\/\/www.krusinsky.cz\/wp-content\/uploads\/2018\/09\/spojov\u00e1n\u00ed-zdroj\u016f-3.jpg 476w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>tak, pokud by m\u011bl men\u0161\u00ed nap\u011bt\u00ed ne\u017e zbyl\u00e9 2 dohromady, tak se jeho nap\u011bt\u00ed ode\u010d\u00edt\u00e1 od nap\u011bt\u00ed zbyl\u00fdch dvou a mezi zelen\u00fdmi body bude jejich rozd\u00edl. Na prav\u00e9m + a na lev\u00e9m -. A pokud by m\u011bl v\u011bt\u0161\u00ed nap\u011bt\u00ed ne\u017e zbyl\u00e9 2 dohromady, tak by se naopak nap\u011bt\u00ed zbyl\u00fdch 2 ode\u010detlo od ozna\u010den\u00e9ho \u010dl\u00e1nku. A v tom p\u0159\u00edpad\u011b by tak\u00e9 byl na zelen\u00fdch bodech rozd\u00edl t\u011bchto nap\u011bt\u00ed, akor\u00e1t na lev\u00e9m zelen\u00e9m bod\u011b + a na prav\u00e9m -.<\/p>\n<p>Pokud byste spojili \u010dl\u00e1nky paraleln\u011b a nespojili byste je v\u0161echny stejn\u00fdmi p\u00f3ly (tj. spojili byste je nap\u0159. + s -), tak by se men\u0161\u00ed nap\u011bt\u00ed jedn\u00e9 polarity ode\u010d\u00edtalo od v\u011bt\u0161\u00edho nap\u011bt\u00ed druh\u00e9 polarity. V\u00fdsledek by byl jejich rozd\u00edl. Plus by byl tam, kde by m\u011blo plus v\u011bt\u0161\u00ed nap\u011bt\u00ed.<\/p>\n<p><strong>!!!B\u011b\u017en\u011b se ale zapojuje pouze prvn\u00ed ze \u010dty\u0159 zp\u016fsob\u016f.<\/strong><br \/>\n<strong>T\u0159et\u00ed se s\u00e9riov\u00fdm zapojen\u00edm, ale obr\u00e1cen\u00fdm jedn\u00edm \u010dl\u00e1nkem se nezapojuje, proto\u017ee\u00a0 kdyby na dvou \u010dl\u00e1nc\u00edch a zbyl\u00e9m jedn\u00e9m byl rozd\u00edl nap\u011bt\u00ed, tak by se p\u0159es z\u00e1t\u011b\u017eov\u00fd obvod za\u010daly \u010dl\u00e1nky navz\u00e1jem nab\u00edjet. A pokud byste nepou\u017eili nab\u00edjec\u00ed nebo pokud u\u017e by byly nabit\u00e9, mohli by se po\u0161kodit. Obecn\u011b toti\u017e v elektrotechnice plat\u00ed pravidlo, \u017ee kdy\u017e p\u0159ipoj\u00edte \u010dl\u00e1nek ke svork\u00e1m dod\u00e1vaj\u00edc\u00edm <a href=\"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/zaklady-vzniku-stridaveho-proudu\/\">stejnosm\u011brn\u00e9 nap\u011bt\u00ed<\/a> kladn\u00fdm p\u00f3lem \u010dl\u00e1nku ke kladn\u00e9mu p\u00f3lu zdroje (svorce) a z\u00e1porn\u00fdm k z\u00e1porn\u00e9 svorce, za\u010dne j\u00edm proch\u00e1zet el. proud a za\u010dne se nab\u00edjet.<\/strong><br \/>\n<strong>Paraleln\u011b se \u010dl\u00e1nky b\u011b\u017en\u011b nespojuj\u00ed ani souhlasnou ani nesouhlasnou polaritou. Souhlasnou tak\u00e9 z toho d\u016fvodu, \u017ee by se mohly za\u010d\u00edt nab\u00edjet. A nesouhlasnou tak\u00e9 ne, proto\u017ee by se za\u010daly sp\u00ed\u0161e naopak vyb\u00edjet, proto\u017ee by navz\u00e1jem uzav\u0159ely el. obvod. A je\u0161t\u011b by tak vznikl zkrat.<br \/>\n<\/strong><\/p>\n<p><strong>\u010cl\u00e1nky se spojuj\u00ed b\u011b\u017en\u011b pouze s\u00e9riov\u011b. Ale pozor! Pouze stejn\u00e9 jmenovit\u00e9 nap\u011bt\u00ed a jmenovit\u00e9 proudy! Jin\u00e9 nap\u011bt\u00ed a proudy pouze v nouzov\u00fdch p\u0159\u00edpadech! Mohly by se tak\u00e9 za\u010d\u00edt navz\u00e1jem nab\u00edjet nesouhlasnou polaritou nebo zni\u010dit!<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Zdroje elekt\u0159iny se d\u011bl\u00ed na: zdroje nap\u011bt\u00ed zdroje proudu Zdroje nap\u011bt\u00ed V oblasti stejnosm\u011brn\u00e9ho nap\u011bt\u00ed a proudu jsou to elektrick\u00e9 \u010dl\u00e1nky funguj\u00edc\u00ed na principu chemick\u00fdch reakc\u00ed a tzv. zdroje stejnosm\u011brn\u00e9ho nap\u011bt\u00ed, kter\u00e9 se p\u0159ipojuj\u00ed do elektrick\u00e9 z\u00e1suvky a na v\u00fdstupu d\u00e1vaj\u00ed zmen\u0161en\u00e9 nap\u011bt\u00ed st\u00e1l\u00e9 polarity a velikosti. Elektrick\u00e9 \u010dl\u00e1nky a baterie jsou tyto: tu\u017ekov\u00e9 (nab\u00edjec\u00ed [&hellip;]<\/p>\n","protected":false},"author":2,"featured_media":0,"parent":100,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_bbp_topic_count":0,"_bbp_reply_count":0,"_bbp_total_topic_count":0,"_bbp_total_reply_count":0,"_bbp_voice_count":0,"_bbp_anonymous_reply_count":0,"_bbp_topic_count_hidden":0,"_bbp_reply_count_hidden":0,"_bbp_forum_subforum_count":0,"footnotes":""},"class_list":["post-89","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/pages\/89","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/comments?post=89"}],"version-history":[{"count":7,"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/pages\/89\/revisions"}],"predecessor-version":[{"id":382,"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/pages\/89\/revisions\/382"}],"up":[{"embeddable":true,"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/pages\/100"}],"wp:attachment":[{"href":"https:\/\/www.krusinsky.cz\/domains\/krusinsky.cz\/wp-json\/wp\/v2\/media?parent=89"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}